# CORREÇÃO DOS EXERCÍCIOS DE NOTAÇÃO CIENTIFICA

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CORREÇÃO DOS EXERCÍCIOS a)3.102 + 4.103 = 3.102+1 + 4.103 = 0,3.103+ 4.103= 4,3.103 b) 3.102 x 4.103 = 12.105 c) 5.104 x 8.105 = 40.109 d) 8.106 : 4.103 = 2.103 e) 4.102 x 5.103 = 4.102+1 + 5.103 = 0,4.103+ 5.103= 5,4.103, f) 6.104 x 4.102= 24.106 g) 3.103 x 7.106 = 21.109 h) 15.106 : 3.103 = 5.103 i) 24.1027 : 6.109 = 4.1018

2 - Resolva os itens a seguir e de a resposta com notação científica: a)8,2.102 x 4.103 = 32,8 .105 b)3,7. 107 : 8,6 . 103 = 0,43.104 c)3,45 . 108 + 6,74 . 10−2 = 3,45.108 + 6,74.10-2+10 = . 3,45 . 108 + 0,000000000674.108 = 3,450000000674.108 d) 4,7 . 10−2 - 5,7 . 10−6 = 4,7 . 10−2 - 5,7 . 10−6+4 = 4,7.10−2 - 0,00057. 10−2 = 4,69943.10-2 e)2,09 . 1010 + 5,55 . 1012 = 2,09.1010+2 + 5,55.1012 = 0,0 209.1012 + 5,55.1012 = 5,5709 .1012 3 – Resolva as operações com Notações Científicas: a) 6,1. 105 + 12 . 102 = 6,1. 105 + 12. 102+3= 6,1. 105 + 0,012 . 105 6,112.105 b) 7,8 . 107 + 136 . 104 = 7,8 .107 + 136 . 104+3 = 7,8 . 107 + 0,136 .107 7,936 . 107 c)5.106- 24.104 = 5.106- 24.104+2 = 5.106- 0,24.106 = 5,24.106 d) 9,2 . 108 - 812 . 105 = 9,2 . 108 - 812 . 105+3 = 9,2 . 108 - 0, 812 . 108 = 8,388.108 e) 6.108+37.107 = 6.108+37.107+1 = 6.108+3,7.108 = 9,7.108

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